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Pearson Algebra 2 Common Core, 2011

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Pearson Algebra 2 Common Core, 2011 View details

Mid-Chapter Quiz

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Exercise 5 Page 579

The given rule means that, after the first term of the sequence, every term a_n is the difference between 5 and the previous term a_(n-1).

1, 4, 1, 4, and 1

Practice makes perfect

We are asked to write the first 5 terms of a sequence, given its recursive rule.

a_1&=1 a_n&=5-a_(n-1), for n>1 To do so, we will use a table.

n	a_n=5-a_(n-1)	5-a_(n-1)	a_n
1	-	-	a_1= 1
2	a_2=5-a_(2-1) ⇕ a_2=5-a_1	a_2=5- a_1 ⇕ a_2=5- 1	a_2= 4
3	a_3=5-a_(3-1) ⇕ a_3=5-a_2	a_3=5- a_2 ⇕ a_3=5- 4	a_3= 1
4	a_4=5-a_(4-1) ⇕ a_4=5-a_3	a_4=5- a_3 ⇕ a_4=5- 1	a_4= 4
5	a_5=5-a_(5-1) ⇕ a_5=5-a_4	a_5=5- a_4 ⇕ a_5=5- 4	a_5=1

Therefore, the first 5 terms of the sequence are 1, 4, 1, 4, and 1.

Subchapter links

Exercises p.579