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Pearson Algebra 2 Common Core, 2011

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Pearson Algebra 2 Common Core, 2011 View details

Mid-Chapter Quiz

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Exercise 4 Page 579

The given rule means that, after the first term of the sequence, every term a_n is the product of 3 and the previous term a_(n-1).

2, 6, 18, 54, and 162

Practice makes perfect

We are asked to write the first 5 terms of a sequence, given its recursive rule.

a_1&=2 a_n&=3a_(n-1), for n>1 To do so, we will use a table.

n	a_n=3a_(n-1)	3a_(n-1)	a_n
1	-	-	a_1= 2
2	a_2=3a_(2-1) ⇕ a_2=3a_1	a_2=3 a_1 ⇕ a_2=3( 2)	a_2= 6
3	a_3=3a_(3-1) ⇕ a_3=3a_2	a_3=3 a_2 ⇕ a_3=3( 6)	a_3= 18
4	a_4=3a_(4-1) ⇕ a_4=3a_3	a_4=3 a_3 ⇕ a_4=3( 18)	a_4= 54
5	a_5=3a_(5-1) ⇕ a_5=3a_4	a_5=3 a_4 ⇕ a_5=3( 54)	a_5=162

Therefore, the first 5 terms of the sequence are 2, 6, 18, 54, and 162.

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Exercises p.579