Pearson Algebra 2 Common Core, 2011
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Pearson Algebra 2 Common Core, 2011 View details
Mid-Chapter Quiz
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Exercise 24 Page 579

To find the arithmetic mean of two numbers, add them and divide by 2.

a_2=11, a_3=18, and a_4=25

Practice makes perfect
We want to find the missing terms of the given arithmetic sequence. 4, a_2, a_3, a_4, 32, ... To accomplish this, we will use the fact that the arithmetic mean of the first and fifth terms is the third term. To find the arithmetic mean of two numbers, we add them and divide by 2. a_3=a_1+a_5/2 Let's substitute 4 for a_1 and 32 for a_5 in the above equation.
a_3=a_1+a_5/2
a_3=4+ 32/2
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Evaluate right-hand side
a_3=36/2
a_3=18
Now we can use the fact that a_1= 4, a_3= 18, and a_5= 32 to find a_2 and a_4 by calculating two more arithmetic means.
a_n=a_(n-1)+a_(n+1)/2
a_2=a_1+a_3/2 a_4=a_3+a_5/2
a_2=4+ 18/2 a_4=18+ 32/2
a_2=22/2 a_4=50/2
a_2=11 a_4=25

Finally, we can complete the sequence. ccccc a_1 & a_2 & a_3 & a_4 & a_5 [0.8em] 4 & 11 & 18 & 25 & 32