Pearson Algebra 2 Common Core, 2011
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Pearson Algebra 2 Common Core, 2011 View details
3. Rational Functions and Their Graphs
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Exercise 63 Page 523

To algebraically determine the inverse, of switch x and y and solve for y. A function is a relation where each input is related to exactly one output.

Inverse of the Function: y=±sqrt(x2)
Result: The inverse is not a function.

Practice makes perfect
We will begin by finding the inverse of y. First, we will switch x and y and solve for y. y=2( x)^2 → x=2( y)^2 The resulting equation will be the inverse of the given function.
x=2(y)^2
â–Ľ
Solve for y
x/2=y^2
sqrt(x/2)=sqrt(y^2)

sqrt(a^2)=± a

± sqrt(x/2)=y
y=± sqrt(x/2)
Now that we have found the inverse of y, we will determine if it is also a function.

Is the Inverse a Function?

A function is a relation where each input is related to exactly one output. In our case, we can see that for each x in the inverse, there are two values of y. If x=a, then y=± sqrt(a2). Therefore, the inverse of the function is not a function.