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Factor by applying the difference of cubes.
x=2/3
To solve the given equation by factoring, we will apply the difference of two cubes. a^3-b^3 ⇔ (a-b)(a^2+ab+b^2) Let's start by factoring out the greatest common factor.
Factor out 2
Write as a power
a^m* b^m=(a * b)^m
a^3-b^3 = (a-b)(a^2+ab+b^2)
Multiply
(a * b)^m=a^m* b^m
Calculate power
Use the Zero Product Property
(I): LHS+2=RHS+2
(I): .LHS /3.=.RHS /3.
From Equation (I), we found that one solution is x= 23. To find other solutions, we will solve Equation (II). Note that since this is a quadratic equation, we will use the Quadratic Formula. ax^2+bx+c=0 ⇔ x=- b±sqrt(b^2-4ac)/2a To do so, we first need to identify a, b, and c. 9x^2+ 6x+ 4=0 We can see above that a= 9, b= 6, and c= 4. Let's substitute these values into the formula and solve for x.
Substitute values
Calculate power
(- a)b = - ab
(- a)b = - ab
Subtract term
Multiply
Split into factors
sqrt(a* b)=sqrt(a)*sqrt(b)
Calculate root
sqrt(- 1)= i
Factor out 6
Cancel out common factors
We found that the solutions for the quadratic equation are x= - 1± isqrt(3)3. Notice that they are not real solutions, thus the only real solution is 23. Real solution x=2/3