Pearson Algebra 2 Common Core, 2011
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Pearson Algebra 2 Common Core, 2011 View details
3. Rational Functions and Their Graphs
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Exercise 45 Page 522

Division by zero is not defined. This means that the denominator cannot be zero.

Practice makes perfect

To graph the given rational function, we will find its domain, asymptotes, and intercepts. Then, we will find points using a table of values. Finally, we will plot and connect those points.

Domain

Consider the given function. y=- x/(x-1)^2 Recall that division by zero is not defined. Therefore, the rational function is undefined where (x-1)^2=0. (x-1)^2=0 ⇔ x=1 This means that x=1 is not included in the domain. Domain All real numbers except x=1

Asymptotes

Asymptotes can be vertical or horizontal lines.

Vertical Asymptotes

Once again, let's consider the given function. y=- x/(x-1)^2 Note that we cannot cancel out common factors. Therefore, there are no holes. Also, if the real number a is not included in the domain, there is a vertical asymptote at x=a. In this case, we have a vertical asymptote at x=1.

Horizontal Asymptotes

To find the horizontal asymptotes, we can use a set of rules. To properly use these rules, in the following table m and n must be the highest degree of the numerator and denominator.

y=ax^m/bx^n Asymptote
m y=0
m>n none
m=n y=a/b
We must expand the denominator of the function.
y=- x/(x-1)^2
y=- x/x^2-2x+1
Let's look at the degrees of the numerator and denominator for our function. y=- x^1/x^2-2x+1 We can see that the degree of the denominator is higher than the degree of the numerator. Therefore, the line y=0 is a horizontal asymptote.

Intercepts

The intercepts of the function are the points at which the graph intersects the axes.

x-intercepts

The x-intercepts are the points where the graph intersects the x-axis. At these points, the value of the y-coordinate is zero. Let's substitute 0 for y in the given function and solve for x.
y=- x/(x-1)^2
0=- x/(x-1)^2
Solve for x
0=- x
0=x
x=0
There is an x-intercept at (0,0).

y-intercept

The y-intercept is the point where the graph intersects the y-axis. At this point, the value of the x-coordinate is zero. Let's substitute 0 for x in the given function and solve for y.
y=- x/(x-1)^2
y=- 0/( 0-1)^2
Solve for x
y=0/(-1)^2
y=0/1
y=0
There is a y-intercept at (0,0).

Graph

Let's make a table of values to graph the given function. Make sure to only use values included in the domain of the function.

x - x/(x-1)^2 y=- x/(x-1)^2
- 4 - 4/( - 4-1)^2 0.16
- 3 - 3/( - 3-1)^2 0.1875
- 2 - 2/( - 2-1)^2 ≈ 0.222
2 2/( 2-1)^2 - 2
3 - 3/( 3-1)^2 ≈ - 0.667

Finally, let's plot and connect the points. Do not forget to draw the asymptotes and to plot the intercepts and holes, if any.