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Division by zero is not defined. This means that the denominator cannot be zero.
To graph the given rational function, we will find its domain, asymptotes, and intercepts. Then, we will find points using a table of values. Finally, we will plot and connect those points.
Consider the given function. y=4x^2-100/2x^2+x-15 This first thing we need to do is factor the denominator of this function.
Write as a sum
Factor out (x+3)
Recall that division by zero is not defined. Therefore, the rational function is undefined where x+3=0 and 2x-5=0. ccc x+3=0 & 2x-5=0 ⇕ & ⇕ x=-3 & x= 52 This means that x=- 3 and x= 52 are not included in the domain.
Asymptotes can be vertical or horizontal lines.
Once again, let's consider the given function. y=4x^2-100/2x^2+x-15 Notice that the numerator can be factored. Let's factor this expression and try to cancel out any common factors between the numerator and the denominator.
Factor out 4
a^2-b^2=(a+b)(a-b)
Recall that we already factored the denominator. Let's look at fully factored fraction.
y=4(x+5)(x-5)/(x+3)(2x-5)
Note that we cannot cancel out common factors. Therefore, there are no holes.
Also, if the real number a is not included in the domain, there is a vertical asymptote at x=a. In this case, we have a vertical asymptote at x=- 3 and x= 52.
To find the horizontal asymptotes, we can use a set of rules. To properly use these rules, in the following table m and n must be the highest degree of the numerator and denominator.
| y=ax^m/bx^n | Asymptote |
|---|---|
| m | y=0 |
| m>n | none |
| m=n | y=a/b |
Now, consider the function one more time. Let's look at the degrees of the numerator and denominator for our function. y=4x^2-100/2x^2+x-15 We can see that the degree of the denominator is equal to the degree of the numerator. Therefore, the line y= 42=2 is a horizontal asymptote.
The intercepts of the function are the points at which the graph intersects the axes.
The x-intercepts are the points where the graph intersects the x-axis. At these points, the value of the y-coordinate is zero. Let's substitute 0 for y in the given function and solve for x.
y= 0
LHS * (2x^2+x-15)=RHS* (2x^2+x-15)
.LHS /4.=.RHS /4.
LHS+25=RHS+25
sqrt(LHS)=sqrt(RHS)
Rearrange equation
There is an x-intercept at (-5,0), and (5,0).
The y-intercept is the point where the graph intersects the y-axis. At this point, the value of the x-coordinate is zero. Let's substitute 0 for x in the given function and solve for y.
x= 0
Zero Property of Multiplication
Identity Property of Addition
- a/- b=a/b
a/b=.a /5./.b /5.
There is a y-intercept at (0, 203 ).
Let's make a table of values to graph the given function. Make sure to only use values included in the domain of the function.
| x | 4x^2-100/2x^2+x-15 | y=4x^2-100/2x^2+x-15 |
|---|---|---|
| - 6 | 4( - 6)^2-100/2( - 6)^2+( -6)-15 | ≈ 0.863 |
| - 4 | 4( - 4)^2-100/2( - 4)^2+( - 4)-15 | ≈ - 2.769 |
| - 2 | 4( - 2)^2-100/2( - 2)^2+( -2)-15 | ≈ 9.333 |
| - 1 | 4( - 1)^2-100/2( - 1)^2+( -1)-15 | ≈ 6.857 |
| 1 | 4( 1)^2-100/2( 1)^2+ 1-15 | 8 |
| 4 | 4( 4)^2-100/2( 4)^2+ 4-15 | ≈ - 1.714 |
| 6 | 4( 6)^2-100/2( 6)^2+ 6-15 | ≈ 0.698 |
Finally, let's plot and connect the points. Do not forget to draw the asymptotes and to plot the intercepts and holes, if any.