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Pearson Algebra 2 Common Core, 2011

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Pearson Algebra 2 Common Core, 2011 View details

4. Rational Expressions

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Exercise 61 Page 533

What is the inverse operation of square root?

x=49

Practice makes perfect

To solve equations with a variable expression inside a radical, we first want to make sure the radical is isolated. Then we can raise both sides of the equation to a power equal to the index of the radical. Let's try to solve our equation using this method!

sqrt(x)-3 = 4

LHS+3=RHS+3

sqrt(x) = 7

LHS^2=RHS^2

(sqrt(x))^2=7^2

( sqrt(a) )^2 = a

x = 7^2

Calculate power

x = 49

Finally, we will check our solution by substituting the value into the original equation.

sqrt(x)-3 = 4

x= 49

sqrt(49)-3 ? = 4

▼

Simplify left-hand side

Calculate root

7-3 ? = 4

Subtract term

4=4 ✓

Subchapter links

Lesson Check p.530

Standardized Test Prep p.533

Mixed Review p.533