Pearson Algebra 2 Common Core, 2011
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Pearson Algebra 2 Common Core, 2011 View details
4. Rational Expressions
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Exercise 54 Page 533

There will be either a hole or a vertical asymptote at the x-value that makes the denominator zero.

Holes: x=3
Vertical Asymptotes: The graph does not have any vertical asymptotes.

Practice makes perfect
Consider the given function. y=x-3/x-3Recall that division by zero is not defined. Therefore, the rational function is undefined where x-3=0. x-3=0 ⇔ x=3 The function is not defined when x=3. This means we have either a hole or a vertical asymptote. Let's now simplify the function.
y=x-3/x-3
y=x-3/x-3
y=1
After simplifying, we can see that the denominator was canceled out. This indicates that the graph has a hole when x=3.