Pearson Algebra 2 Common Core, 2011
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Pearson Algebra 2 Common Core, 2011 View details
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Exercise 20 Page 461

Use the definition of a logarithm.

log_(12)8=- 3

Practice makes perfect
To write the given equation in logarithmic form, we should recall the definition of a logarithm.

x= b^y ⇔ log_b x=y The above relationship tells us that the logarithm y is the exponent to which b must be raised to get x. Let's now apply the definition to the given equation. 8=( 1/2)^(- 3) ⇔ log_(12) 8=- 3 The above means that - 3 is the exponent to which 12 must be raised to obtain 8.