To write the given equation in logarithmic form, we should recall the definition of a logarithm.
x= b^y ⇔ log_b x=y
The above relationship tells us that the logarithm y is the exponent to which b must be raised to get x. Let's now apply the definition to the given equation.
8=( 1/2)^(- 3) ⇔ log_(12) 8=- 3
The above means that - 3 is the exponent to which 12 must be raised to obtain 8.