Pearson Algebra 2 Common Core, 2011
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Pearson Algebra 2 Common Core, 2011 View details
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Exercise 19 Page 461

Use the definition of a logarithm.

log_41/4=- 1

Practice makes perfect
To write the given equation in logarithmic form, we should recall the definition of a logarithm.

x= b^y ⇔ log_b x=y The above relationship tells us that the logarithm y is the exponent to which b must be raised to get x. Let's now apply the definition to the given equation. 4^(- 1)= 1/4 ⇔ log_4 14=- 1 The above means that - 1 is the exponent to which 4 must be raised to obtain 14.