Pearson Algebra 2 Common Core, 2011
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Pearson Algebra 2 Common Core, 2011 View details
Mid-Chapter Quiz
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Exercise 10 Page 461

Start by performing a compression.

Practice makes perfect
We want to graph the given exponential function as a transformation of its parent function. y= 12(5)^(x- 1)+ 4 Looking at the function, we can see that it has been compressed by a factor of 12, translated 1 unit to the right, and translated 4 units up. Let's show the transformations one at a time.

Compression

Let's start by considering the parent function y=5^x. If we multiply 5^x by 12, we obtain a vertical compression by a factor of 12. The resulting function is y= 12 (5)^x.

Horizontal Translation

Now, we need to consider the function y= 12(5)^(x-1). This is a horizontal translation of y= 12(5)^x to the right by 1 unit.

Vertical Translation

Finally, we will consider the function y= 12(5)^(x-1)+4. This is a vertical translation of y= 12(5)^(x-1) up by 4 units.

Extra

Possible Transformations

The following table illustrates the general form for all possible transformations of functions.

Transformations of f(x)
Vertical Translations Translation up k units, k>0 y=f(x)+ k
Translation down k units, k>0 y=f(x)- k
Horizontal Translations Translation right h units, h>0 y=f(x- h)
Translation left h units, h>0 y=f(x+ h)
Vertical Stretch or Compression Vertical stretch, a>1 y= af(x)
Vertical compression, 0< a< 1 y= af(x)
Horizontal Stretch or Compression Horizontal stretch, 0< b<1 y=f( bx)
Horizontal compression, b>1 y=f( bx)
Reflections In the x-axis y=- f(x)
In the y-axis y=f(- x)