Pearson Algebra 2 Common Core, 2011
PA
Pearson Algebra 2 Common Core, 2011 View details
Cumulative Standards Review

Exercise 15 Page 494

Start by using the Change of Base Formula.

x=1

Practice makes perfect
We want to solve an equation involving more than one logarithm. To do so, we will start by using the Change of Base Formula. log_c a = log a/log cWhere log a represents represents the common logarithm of a.
log_9x=log_6x

log_c a = log_b a/log_b c

log x/log 9 = log x/log 6
log x/log 9 - log x/log 6 = 0
log x ( 1/log 9 - 1/log 6) = 0
Now, we should recall the Zero Product Property to find the solution of the given equation. Since the equation is already written in factored form, we can already use the Zero Product Property. Taking into consideration, that 1log 9 - 1log 6 is a number different than 0, we can obtain the solution. log x ( 1/log 9 - 1/log 6) = 0 ⇕ log x=0 ⇕ x=1

Checking Our Answer

Checking the answer
To check our answer, we will substitute 1 for x in the given equation.
log_9x=log_6x
log_9 1 ? = log_6 1

log_9(1) = 0 & log_6(1) = 0

0=0 âś“
Since substituting 1 for x in the given equation produces a true statement, our answer is correct.