Pearson Algebra 2 Common Core, 2011
PA
Pearson Algebra 2 Common Core, 2011 View details
Cumulative Standards Review

Exercise 7 Page 493

To simplify the given expression, use the Properties of Exponents.

A

Practice makes perfect
To simplify the given expression, we will use the Properties of Exponents. We will try to eliminate the exponent by splitting the terms into perfect cube factors. Let's do it!
sqrt(72x^5y^3z^8)/sqrt(3xy^2z^2)
sqrt(72x^5y^3z^8/3xy^2z^2)
sqrt(72/3 * x^5/x * y^3/y^2 * z^8/z^2)
sqrt(24 * x^5/x * y^3/y^2 * z^8/z^2)
sqrt(24 * x^(5-1) * y^(3-2) * z^(8-2))
sqrt(24 * x^4 * y^1 * z^6)
sqrt(24 * x^4 * y * z^6)
sqrt(24 * x^(2 * 2) * y * z^(3 * 2))
sqrt(24 * (x^2)^2 * y * (z^3 )^2)
sqrt(24) * sqrt((x^2)^2) * sqrt(y) * sqrt((z^3 )^2)
sqrt(24) * |x^2| * sqrt(y) * |z^3|
sqrt(4 * 6) * |x^2| * sqrt(y) * |z^3|
sqrt(4) * sqrt(6) * |x^2| * sqrt(y) * |z^3|
2 * sqrt(6) * |x^2| * sqrt(y) * |z^3|
2 * |x^2| * |z^3| * sqrt(6) * sqrt(y)
2 * |x^2| * |z^3| * sqrt(6y)
Since x^2 is a non-negative real number for exery x value, we can rewrite our expression to the simplest form. 2 * |x^2| * |z^3| * sqrt(6y) ⇕ 2 x^2|z^3| sqrt(6y) Therefore, looking at possible answers, only A corresponds well to our exercise.