Pearson Algebra 2 Common Core, 2011
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Pearson Algebra 2 Common Core, 2011 View details
2. Polynomials, Linear Factors, and Zeros
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Exercise 4 Page 293

Recall the Factor Theorem.

f(x)=x^3-x

Practice makes perfect

We want to write a polynomial function in standard form with the given zeros. To do so, we will use the Factor Theorem to write the factored form. We will then simplify it by applying the Distributive Property. Let's first recall the Factor Theorem.

Factor Theorem

The expression x-a is a factor of a polynomial if and only if the value a is a zero of the related polynomial function.

We know that - 1, 1, and 0 are zeros of our function. Therefore, we can write our polynomial function as the product of three factors. f(x) = ( x-( - 1) ) ( x- 1) ( x- 0) ⇕ f(x)=(x+1)(x-1)x Finally, we can apply the Distributive Property to express the function in standard form.
f(x)=(x+1)(x-1)x
f(x)=(x+1)(x^2-x)
â–Ľ
Simplify right-hand side
f(x)=x(x^2-x)+(x^2-x)
f(x)=( x^3-x^2 )+(x^2-x)
f(x)=x^3-x^2+x^2-x
f(x)=x^3-x

Checking Our Answer

Checking Our Answer
We can check our answer by substituting the given zeros for x. If the result is f(x)=0, it means that the given numbers are actually zeros of the function and our answer is correct. Let's start by checking - 1.
f(x)=x^3-x
f( - 1)=( - 1)^3-( - 1)
â–Ľ
Evaluate right-hand side
f(- 1)=- 1-(- 1)
f(- 1)=- 1+1
f(- 1)=0 âś“
We proved that - 1 is a zero of the function. Let's now check 1.
f(x)=x^3-x
f( 1)=( 1)^3- 1
â–Ľ
Evaluate right-hand side
f(1)=1-1
f(1)=0 âś“
We have shown that 1 is also a zero. Finally, let's see what happens with 0.
f(x)=x^3-x
f( 0)=( 0)^3- 0
â–Ľ
Evaluate right-hand side
f(0)=0-0
f(0)=0 âś“
We found that 0 is also a zero. Since - 1, 1 and 0 are zeros of the polynomial function, our answer is correct.