Pearson Algebra 2 Common Core, 2011
PA
Pearson Algebra 2 Common Core, 2011 View details
8. Polynomial Models in the Real World
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Exercise 44 Page 338

Expand the expression by using the Pascal's Triangle and the Binomial Theorem.

1331x^3-363x^2+33x-1

Practice makes perfect

To expand the given binomial, we should recall the Binomial Theorem. It states that for every positive integer n, we can expand the expression (a+b)^n by using the numbers in the n^(th) row of Pascal's Triangle. cc (a+b)^n= & P_0a^nb^0+P_1a^(n-1)b^1 & + & ... & + & P_(n-1)a^1b^(n-1)+P_na^0b^n In the above formula, P_0, P_1, ..., P_n are the numbers in the n^(th) row of Pascal's Triangle. Row 1.3cm Pascal's Triangle 1.2cm cccccccccccc 0 & & & & & & 1 & & & & & 1 & & & & & 1 & & 1 & & & & 2 & & & & 1 & & 2 & & 1 & & & 3 & & & 1 & & 3 & & 3 & & 1 & & 4 & & 1 & & 4 & & 6 & & 4 & & 1 & 5 & 1 & & 5 & & 10 & & 10 & & 5 & & 1 Note that each number greater than 1 found in the triangle is the sum of the two numbers diagonally above it. Now consider the given binomial. ( 11x - 1)^3 ⇔ ( 11x+( - 1))^3 We can substitute the first term for a and the second term for b using the Binomial Theorem equation and the coefficients from Pascal's Triangle.

(a+b)^n=P_0a^nb^0+P_1a^(n-1)b^1+... +P_(n-1)a^1b^(n-1)+P_na^0b^n
( 11x+( - 1))^3= 1( 11x)^3( - 1)^0+ 3( 11x)^2( - 1)^1+ 3( 11x)^1( - 1)^2+ 1( 11x)^0( - 1)^3

Finally, let's simplify the expression.

1(11x)^3(- 1)^0+3(11x)^2(- 1)^1+3(11x)^1(- 1)^2+1(11x)^0(- 1)^3
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Simplify
1(11x)^3(1)+3(11x)^2(- 1)^1+3(11x)^1(- 1)^2+1(1)(- 1)^3
1(11x)^3(1)+3(11x)^2(- 1)+3(11x)(- 1)^2+1(1)(- 1)^3
(11x)^3+3(11x)^2(- 1)+3(11x)(- 1)^2+(- 1)^3
(11)^3(x)^3+3(11)^2(x)^2(- 1)+3(11x)(- 1)^2+(- 1)^3
(1331)(x)^3+3(121)(x)^2(- 1)+3(11x)(1)+(- 1)
1331x^3-363x^2+33x-1