Pearson Algebra 2 Common Core, 2011
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Pearson Algebra 2 Common Core, 2011 View details
Concept Byte: Graphing Polynomials Using Zeros
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Exercise 4 Page 325

How can you find the x-intercepts of a function written in factored form?

Sketch:

Graphing calculator:

Practice makes perfect

To sketch the graph of a function, we must find its zeros and determine how the function changes around these points. Since the function is already in factored form, we can determine the zeros by substituting h(x)=0 and then using the Zero Product Property.

h(x)=(x+2)(x-3)(x+1)(x-1)
0=(x+2)(x-3)(x+1)(x-1)
lcx+2=0 & (I) x-3=0 & (II) x+1=0 & (III) x-1=0 & (IV)
(I), (II), (III), (IV): Solve for x
lx=- 2 x-3=0 x+1=0 x-1=0
lx=- 2 x=3 x+1=0 x-1=0
lx=- 2 x=3 x=- 1 x-1=0
lx_1=- 2 x_2=3 x_3=- 1 x_4=1

When we know a function's x-intercepts, we can plot them in a coordinate plane.

If we know how the function moves around these points, we get an idea of what it looks like. In order to do that, we can calculate the h-values of the following intervals. Note that h represents the function's values for different values of x. x&<- 2 - 2< x& < - 1 - 1< x& < 1 1< x& < 3 3< x& Let's choose some arbitrary x-values in these intervals and find their corresponding h-values.

Interval x (x+2)(x-3)(x+1)(x-1) h
x<- 2 - 3 ( - 3+2)( - 3-3)( - 3+1)( - 3-1) 48
- 2 < x < - 1 - 1.5 ( - 1.5+2)( - 1.5-3)( - 1.5+1)( - 1.5-1) ≈ - 2.8
- 1 < x < 1 0 ( 0+2)( 0-3)( 0+1)( 0-1) 6
1 < x < 3 2 ( 2+2)( 2-3)( 2+1)( 2-1) - 12
3 < x 4 ( 4+2)( 4-3)( 4+1)( 4-1) 90

With the possible exception of the y-intercept, the actual h-values for the given x-values we used are not important. Instead, we are more interested if the function is above or below the x-axis in the given intervals. This will tell us how the function grows, which we can use to sketch the graph. h(- 3)&= 48 &&⇒ Abovethex-axis h(- 1.5)&≈ - 2.8 &&⇒ Belowthex-axis h(0)& = 6 &&⇒ Abovethex-axis h(2)& = - 12 &&⇒ Belowthex-axis h(4)& = 90 &&⇒ Abovethex-axis Going from above the x-axis to below the x-axis means the function is decreasing, and vice-versa. With this information, we can sketch the graph. We will draw it so that it intercepts the y-axis at (0,6). From our randomly chosen substitutions, we also know that it should pass through (2,- 12). Adding these points to the diagram will help to make a better sketch.

Now let's graph the function on our graphing calculator and compare. Notice that we can use the same window-setting as in our sketch to make sure the proportions are the same.

The graphing calculator image is very similar to our graph.