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Expand the expression by using the Pascal's Triangle and the Binomial Theorem.
108
To find the coefficient of the x^2 term of the binomial expansion, we should recall the Binomial Theorem. It states that for every positive integer n, we can expand the expression (a+b)^n by using the numbers in the n^(th) row of Pascal's Triangle.
(a+b)^n
=
P_0a^nb^0+P_1a^(n-1)b^1+... +P_(n-1)a^1b^(n-1)+P_na^0b^n
In the above formula, P_0, P_1, ..., P_n are the numbers in the n^(th) row of Pascal's Triangle.
| (a+b)^n=P_0a^nb^0+P_1a^(n-1)b^1+... +P_(n-1)a^1b^(n-1)+P_na^0b^n |
|---|
| ( 3x+ 4)^3= 1( 3x)^3( 4)^0+ 3( 3x)^2( 4)^1+ 3( 3x)^1( 4)^2+ 1( 3x)^0( 4)^3 |
Finally, let's simplify the expression.
a^0=1
a^1=a
a * 1=a
(a * b)^m=a^m* b^m
Calculate power
Multiply
The coefficient of the x^2 term of this expansion is 108.