Pearson Algebra 2 Common Core, 2011
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Pearson Algebra 2 Common Core, 2011 View details
Chapter Review
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Exercise 78 Page 351

Expand the expression by using the Pascal's Triangle and the Binomial Theorem.

x^6+6x^5+15x^4+20x^3+15x^2+6x+1

Practice makes perfect

To expand the binomial, we should recall the Binomial Theorem. It states that for every positive integer n, we can expand the expression (a+b)^n by using the numbers in the n^(th) row of Pascal's Triangle. (a+b)^n = P_0a^nb^0+P_1a^(n-1)b^1+... +P_(n-1)a^1b^(n-1)+P_na^0b^n In the above formula, P_0, P_1, ..., P_n are the numbers in the n^(th) row of Pascal's Triangle. l&l&l&l&l&l&l&l&l&l&l&l&l&l Row&&&&&&Pascal's&&&&&&& &&&&&&Triangle&&&&&&& c&c&c&c&c&c&c&c&c&c&c&c 0& & & & & & &1 & & & & & & 1& & & & & &1 & &1 & & & & & 2& & & & &1 & &2 & &1 & & & & 3& & & &1 & &3 & &3 & &1 & & & 4& & &1 & &4 & &6 & &4 & &1 & & 5 & &1 & &5 & &10 & &10 & &5 & &1 6 & 1 & & 6 & & 15 & & 20 & & 15 & & 6 & & 1 Note that each number found in the triangle that is the sum of the two numbers diagonally above it. Now consider the given binomial. ( x+ 1 )^6 We can substitute the first term for a and the second term for b using the Binomial Theorem equation and the coefficients from Pascal's Triangle.

(a+b)^n=P_0a^nb^0+P_1a^(n-1)b^1+... +P_(n-1)a^1b^(n-1)+P_na^0b^n
( x+ 1)^6= 1( x)^6( 1)^0+ 6( x)^5( 1)^1+ 15( x)^4( 1)^2+ 20( x)^3( 1)^3+ 15( x)^2( 1)^4+ 6( x)^1( 1)^5+ 1( x)^0( 1)^6

Finally, let's simplify the expression.

1(x)^6(1)^0+6(x)^5(1)^1+15(x)^4(1)^2+20(x)^3(1)^3+15(x)^2(1)^4+6(x)^1(1)^5+1(x)^0(1)^6
â–¼
Simplify
1(x)^6(1)+6(x)^5(1)^1+15(x)^4(1)^2+20(x)^3(1)^3+15(x)^2(1)^4+6(x)^1(1)^5+1(1)(1)^6
1(x)^6(1)+6(x)^5(1)+15(x)^4(1)^2+20(x)^3(1)^3+15(x)^2(1)^4+6x(1)^5+1(1)(1)^6
x^6+6(x)^5+15(x)^4(1)^2+20(x)^3(1)^3+15(x)^2(1)^4+6x(1)^5+1^6
x^6+6x^5+15x^4(1)+20x^3(1)+15x^2(1)+6x(1)+1
x^6+6x^5+15x^4+20x^3+15x^2+6x+1