Pearson Algebra 2 Common Core, 2011
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Pearson Algebra 2 Common Core, 2011 View details
Chapter Review
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Exercise 75 Page 351

Expand the expression by using the Pascal's Triangle and the Binomial Theorem.

x^3-15x^2+75x-125

Practice makes perfect

To expand the binomial, we should recall the Binomial Theorem. It states that for every positive integer n, we can expand the expression (a+b)^n by using the numbers in the n^(th) row of Pascal's Triangle. (a+b)^n = P_0a^nb^0+P_1a^(n-1)b^1+... +P_(n-1)a^1b^(n-1)+P_na^0b^n In the above formula, P_0, P_1, ..., P_n are the numbers in the n^(th) row of Pascal's Triangle. l&l&l&l&l&l&l&l&l&l&l&l&l&l Row&&&&&&Pascal's&&&&&&& &&&&&&Triangle&&&&&&& c&c&c&c&c&c&c&c&c&c&c&c 0& & & & & &1 & & & & & 1& & & & &1 & &1 & & & & 2& & & &1 & &2 & &1 & & & 3& & & 1 & & 3 & & 3 & & 1 & & 4& &1 & &4 & &6 & &4 & &1 & 5&1 & &5 & &10 & &10 & &5 & &1 Note that each number found in the triangle that is the sum of the two numbers diagonally above it. Now consider the given binomial. ( x -5 )^3 We can substitute the first term for a and the second term for b using the Binomial Theorem equation and the coefficients from Pascal's Triangle.

(a+b)^n=P_0a^nb^0+P_1a^(n-1)b^1+... +P_(n-1)a^1b^(n-1)+P_na^0b^n
( x -5)^3= 1( x)^3( -5)^0+ 3( x)^2( -5)^1+ 3( x)^1( -5)^2+ 1( x)^0( -5)^3

Finally, let's simplify the expression.

1(x)^3(-5)^0+3(x)^2(-5)^1+3(x)^1(-5)^2+1(x)^0(-5)^3
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Simplify
1(x)^3(1)+3(x)^2(-5)^1+3(x)^1(-5)^2+1(1)(-5)^3
1(x)^3(1)+3(x)^2(-5)+3(x)(-5)^2+1(1)(-5)^3
x^3+3(x)^2(-5)+3(x)(-5)^2+(-5)^3
x^3+3x^2(-5)+3(x)(25)+(-125)
x^3+(-15)x^2+75x+(-125)
x^3-15x^2+75x-125