Pearson Algebra 2 Common Core, 2011
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Pearson Algebra 2 Common Core, 2011 View details
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Exercise 73 Page 351

Expand the expression by using the Pascal's Triangle and the Binomial Theorem.

b^4+8b^3+24b^2+32b+16

Practice makes perfect

To expand the binomial, we should recall the Binomial Theorem. It states that for every positive integer n, we can expand the expression (a+b)^n by using the numbers in the n^(th) row of Pascal's Triangle. (a+b)^n = P_0a^nb^0+P_1a^(n-1)b^1+... +P_(n-1)a^1b^(n-1)+P_na^0b^n In the above formula, P_0, P_1, ..., P_n are the numbers in the n^(th) row of Pascal's Triangle. l&l&l&l&l&l&l&l&l&l&l&l&l&l Row&&&&&&Pascal's&&&&&&& &&&&&&Triangle&&&&&&& c&c&c&c&c&c&c&c&c&c&c&c 0& & & & & &1 & & & & & 1& & & & &1 & &1 & & & & 2& & & &1 & &2 & &1 & & & 3& & &1 & &3 & &3 & &1 & & 4& & 1 & & 4 & & 6 & & 4 & & 1 & 5&1 & &5 & &10 & &10 & &5 & &1 Note that each number found in the triangle that is the sum of the two numbers diagonally above it. Now consider the given binomial. ( b+ 2 )^4 We can substitute the first term for a and the second term for b using the Binomial Theorem equation and the coefficients from Pascal's Triangle.

(a+b)^n=P_0a^nb^0+P_1a^(n-1)b^1+... +P_(n-1)a^1b^(n-1)+P_na^0b^n
( b+ 2)^4= 1 b^4( 2)^0+ 4 b^3( 2)^1+ 6 b^2( 2)^2+ 4 b^1( 2)^3+ 1 b^0( 2)^4

Finally, let's simplify the expression.

1b^4(2)^0+4b^3(2)^1+6b^2(2)^2+4b^1(2)^3+1b^0(2)^4
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Simplify
1b^4(1)+4b^3(2)^1+6b^2(2)^2+4b^1(2)^3+1(1)(2)^4
1b^4(1)+4b^3(2)+6b^2(2)^2+4b(2)^3+1(1)(2)^4
b^4+4b^3(2)+6b^2(2)^2+4b(2)^3+2^4
b^4+4b^3(2)+6b^2(4)+4b(8)+16
b^4+8b^3+24b^2+32b+16