Pearson Algebra 2 Common Core, 2011
PA
Pearson Algebra 2 Common Core, 2011 View details
Chapter Review
Continue to next subchapter

Exercise 57 Page 350

Observe the number of sign changes that occur in P(x) and P(- x).

Two or no positive real zeros, one negative real zero.

Practice makes perfect

We can use Descartes' Rule of Signs to learn about the number of positive and negative real zeros for the given polynomial function. Let P(x) be a polynomial with real coefficients written in standard form.

  • The number of positive real roots of P(x)=0 is either equal to the number of sign changes between consecutive coefficients of P(x) or is less than that by an even number.
  • The number of negative real roots of P(x)=0 is either equal to the number of sign changes between consecutive coefficients of P(- x) or is less than that by an even number.

Positive Real Zeros

Consider the given polynomial P(x). P(x)= - 3x^3+11x^2+12x- 8 We can see above that there are two sign changes, ( -) to (+) and (+) to ( -). Therefore, there are either 2 or 0 positive real zeros.

Negative Real Zeros

Now consider P(- x). P(- x)=- 3(- x)^3+11(- x)^2+12(- x)-8 ⇕ P(- x)=3x^3+11x^2- 12x- 8 We can see that there is only one sign change, (+) to ( -). Thus, there is only one negative real zeros.