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Pearson Algebra 2 Common Core, 2011

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Pearson Algebra 2 Common Core, 2011 View details

Chapter Review

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Exercise 52 Page 350

If a is a root of P(x)=0, then (x-a) is a factor of P(x).

P(x)=x^2-17x+70

Practice makes perfect

We want to write a polynomial function with rational coefficients so that P(x)=0 has the given roots. 7 and 10

Recall that if a is a root of P(x)=0, then (x-a) is a factor of P(x).

Root	Factor
7	x-7
10	x-10
Polynomial	P(x)= (x-7) (x-10)

Let's simplify the polynomial by applying the Distributive Property.

(x-7)(x-10)

Distribute (x-10)

x(x-10)-7(x-10)

▼

Distribute x & - 7

Distribute x

x^2-10x-7(x-10)

Distribute - 7

x^2-10x-7x+70

Subtract terms

P(x)=x^2-17x+70

Subchapter links

Exercises p.347-352