Pearson Algebra 2 Common Core, 2011
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Pearson Algebra 2 Common Core, 2011 View details
Chapter Review
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Exercise 32 Page 349

Divide until the degree of the divisor is greater than the degree of the dividend.

2x^2+x-3, R 1

Practice makes perfect

To divide the given polynomials using polynomial long division, all the terms of the dividend must be present. Since there are no missing terms, we do not need to rewrite the polynomial. 2x^3-7x^2-7x+13Let's divide!

l r x - 4 & |l 2x^3 - 7x^2 - 7x + 13
â–¼
Divide

2x^3/x= 2x^2

r 2x^2 r x-4 & |l 2x^3 - 7x^2 - 7x + 13

Multiply term by divisor

r 2x^2 rl x-4 & |l 2x^3 - 7x^2 - 7x + 13 & 2x^3 -8x^2

Subtract down

r 2x^2 r x-4 & |l x^2 - 7x + 13
â–¼
Divide

x^2/x= x

r 2x^2+x r x-4 & |l x^2 - 7x + 13

Multiply term by divisor

r2x^2 + x rl x-4 & |l x^2 - 7x + 13 & x^2-4x

Subtract down

r 2x^2 +x r x-4 & |l - 3x + 13
â–¼
Divide

- 3x/x= - 3

r 2x^2 + x - 3 r x-4 & |l - 3x + 13

Multiply term by divisor

r2x^2 + x - 3 rl x-4 & |l - 3x + 13 & - 3x+12

Subtract down

r 2x^2 +x -3 r x-4 & |l 1

The quotient is 2x^2+x-3 with a remainder of 1.
We can check our answer. If it is correct, then the product of the quotient and the divisor, plus the remainder, will be equal to the dividend.

Showing Our Work

Long division by hand...
When we are doing long division by hand, it looks a bit different than how we have it in this solution. Here is how yours should look when you are writing it in your notebook.