Pearson Algebra 2 Common Core, 2011
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Pearson Algebra 2 Common Core, 2011 View details
Chapter Review
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Exercise 25 Page 349

How can factoring out the GCF help you apply the Zero Product Property?

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Practice makes perfect

To solve the given equation by factoring, we will start by writing all the terms on the left-hand side. Then, we will factor out the GCF. Afterwards, we will apply the Zero Product Property to solve the equation.

4x^2=- 4x-1
4x^2+4x=- 1
4x^2+4x+1=0

Since the GCF is 1, we did not need to factor anything out in this situation. To find the solutions, we will solve the equation. Note that this is a quadratic equation. Thus, we will use the Quadratic Formula.

ax^2+bx+c=0 ⇔ x=- b±sqrt(b^2-4ac)/2a To do so, we first need to identify a, b, and c. 4x^2+4x+1=0 ⇔ 4x^2+ 4x+ 1=0 We see that a= 4, b= 4, and c= 1. Let's substitute these values into the formula and solve for x.

x=- b±sqrt(b^2-4ac)/2a
x=- ( 4)±sqrt(( 4)^2-4( 4)( 1))/2( 4)
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Solve for x
x=- 4±sqrt(16-4(4)(1))/2(4)
x=- 4±sqrt(16-16)/8
x=- 4±sqrt(0)/8
x=- 4± 0/8

Note that adding and subtracting 0 will result in the same answer. Therefore, the equation will only have one solution. Solution x= - 4± 08= -48=- 12