Pearson Algebra 2 Common Core, 2011
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Pearson Algebra 2 Common Core, 2011 View details
Chapter Review
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Exercise 24 Page 349

How can factoring out the GCF help you apply the Zero Product Property?

3, 8

Practice makes perfect

To solve the given equation by factoring, we will start by writing all the terms on the left-hand side. Then, we will factor out the GCF. Afterwards, we will apply the Zero Product Property to solve the equation.

x^2-11x=-24
x^2-11x+24=0

Since the GCF is 1, we did not need to factor anything out in this situation. To find the solutions, we will solve the equation. Note that this is a quadratic equation. Thus, we will use the Quadratic Formula.

ax^2+bx+c=0 ⇔ x=- b±sqrt(b^2-4ac)/2a To do so, we first need to identify a, b, and c. x^2-11x+24=0 ⇔ 1x^2+( - 11)x+ 24=0 We see that a= 1, b= - 11, and c= 24. Let's substitute these values into the formula and solve for x.

x=- b±sqrt(b^2-4ac)/2a
x=- ( - 11)±sqrt(( - 11)^2-4( 1)( 24))/2( 1)
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Solve for x
x=11±sqrt((- 11)^2-4(1)(24))/2(1)
x=11±sqrt(121-4(1)(24))/2(1)
x=11±sqrt(121-96)/2
x=11±sqrt(25)/2
x=11± 5/2

The solutions for this equation are x= 11± 52. Let's separate them into the positive and negative cases.

x=11± 5/2
x_1=11+5/2 x_2=11-5/2
x_1=16/2 x_2=6/2
x_1=8 x_2=3

Using the Quadratic Formula, we found that the solutions of the given equation are x_1=8 and x_2=3. These solutions to the quadratic equation are also solutions for the given equation.