Sign In
Think of the process as multiplying two binomials in reverse.
(k+3)(k-8)
To factor a trinomial with a leading coefficient of one, think of the process as multiplying two binomials in reverse. Let's start by taking a look at the constant term.
k^2-5k - 24
In this case, we have - 24. This is a negative number, so for the product of the constant terms in the factors to be negative, these constants must have the opposite sign (one positive and one negative).
| Factor Constants | Product of Constants |
|---|---|
| 1 and - 24 | - 24 |
| - 1 and 24 | - 24 |
| 2 and - 12 | - 24 |
| - 2 and 12 | - 24 |
| 3 and - 8 | - 24 |
| - 3 and 8 | - 24 |
| 4 and - 6 | - 24 |
| - 4 and 6 | - 24 |
Next, let's consider the coefficient of the linear term. k^2 - 5k - 24 For this term, we need the sum of the factors that produced the constant term to equal the coefficient of the linear term, - 5.
| Factors | Sum of Factors |
|---|---|
| 1 and - 24 | - 23 |
| - 1 and 24 | 23 |
| 2 and - 12 | - 10 |
| - 2 and 12 | 10 |
| 3 and - 8 | - 5 |
We found the factors whose product is - 24 and whose sum is - 5. k^2 - 5k - 24 ⇔ (k+3)(k-8)
Distribute k-8
Distribute k
Distribute 3
Add terms
After applying the Distributive Property and simplifying, the result is the same as the given expression. Therefore, we can be sure our solution is correct!