Pearson Algebra 2 Common Core, 2011
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Pearson Algebra 2 Common Core, 2011 View details
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Exercise 5 Page 191

Start by graphing the line, then use the Slope Formula to find its slope.

Equation: y=9x-10
Graph:

Practice makes perfect

First let's graph the given points and connect them with a line.

Now we will write the equation in slope-intercept form. y= mx+b For an equation in this form, m is the slope and b is the y-intercept. Let's use the given points to calculate m. We will start by substituting the points into the Slope Formula.
m=y_2-y_1/x_2-x_1
m=17-( -1)/3- 1
Simplify right-hand side
m=17+1/3-1
m=18/2
m= 9
A slope of 9 means that for every horizontal step in the positive direction, we take 9 vertical steps in the positive direction. Now that we know the slope, we can write a partial version of the equation. y= 9 x+b To complete the equation, we also need to determine the y-intercept b. Since we know that the given points will satisfy the equation, we can substitute one of them into the equation to solve for b. Let's use ( 1, -1).
y=9x+b
-1=9( 1)+b
Solve for b
-1=9+b
-10=b
b=-10
A y-intercept of -10 means that the line crosses the y-axis at the point (0,-10). We can now complete the equation. y= 9x+(-10) ⇒ y=9x-10