Pearson Algebra 2 Common Core, 2011
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Pearson Algebra 2 Common Core, 2011 View details
6. Solving Systems Using Matrices
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Exercise 47 Page 181

Use row operations to solve the matrix.

(1/8,-1/17)

Practice makes perfect
We will first rewrite the system by substituting m and n for 1x and 1y, respectively.
7x+ 3y=5 & (I) 2x+ 1y=-1 & (II)

(I), (II): Write fraction as a mixed number

7 1x+3 1y=5 2 1x+ 1y=-1

(I), (II): 1/x= m, 1/y= n

7 m+3 n=5 2 m+ n=-1
Now we can write the system as a matrix.

Matrix

To rewrite the system of equations as a matrix, we need to consider how the elements of the system relate to the elements of a matrix.
  • The equals signs in the system of equations are represented with a vertical bar in the matrix.
  • The coefficients of the variables form the columns on the left-hand side of the bar.
  • The constants form the column on the right-hand side of the bar.

Below we demonstrate this in a generalized form. a_(11)m+ a_(12)n=c_1 a_(21)m+ a_(22)n=c_2 ⇕ [ cc|c a_(11) & a_(12) & c_1 a_(21) & a_(22) & c_2 ] When each equation in the system is written in the same order, we can consider the coefficients of the variables and the constants. 7m+ 3n=5 2m+ 1n=-1 Now that we have identified all of the variables and constants, we can place them in a matrix. [ cc|c 7 & 3 & 5 2 & 1 & -1 ]

Solving the Matrix

In order to solve the matrix, we will use row operations to obtain a matrix in the following form. [ cc|c 1 & 0 & a 0 & 1 & b ] This final matrix represents the solution of the system of equations, where m= a and n= b. Let's solve the matrix!
[ cc|c7 & 3 & 5 2 & 1 & -1 ]
[ cc|c7 & 3 & 5 6 & 3 & -3 ]
[ cc|c7- 6 & 3- 3 & 5-( -3) 6 & 3 & -3 ]
[ cc|c1 & 0 & 8 6 & 3 & -3 ]
[ cc|c1 & 0 & 8 2 & 1 & -1 ]
[ cc|c2 & 0 & 16 2 & 1 & -1 ]
[ cc|c2 & 0 & 16 2- 2 & 1- 0 & -1- 16 ]
[ cc|c2 & 0 & 16 0 & 1 & -17 ]
[ cc|c1 & 0 & 8 0 & 1 & -17 ]
We have found that m=8 and n=-17. Now we can find x and y. m&=1/x= 8/1 ⇒ x=1/8 n&=1/y=-17/1 ⇒ y=-1/17 The solution of the system is the point ( 18,- 117).