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Use row operations to solve the matrix.
(1/8,-1/17)
We will first rewrite the system by substituting m and n for 1x and 1y, respectively.
(I), (II): Write fraction as a mixed number
(I), (II): 1/x= m, 1/y= n
Now we can write the system as a matrix.
To rewrite the system of equations as a matrix, we need to consider how the elements of the system relate to the elements of a matrix.
Below we demonstrate this in a generalized form. a_(11)m+ a_(12)n=c_1 a_(21)m+ a_(22)n=c_2 ⇕ [ cc|c a_(11) & a_(12) & c_1 a_(21) & a_(22) & c_2 ] When each equation in the system is written in the same order, we can consider the coefficients of the variables and the constants. 7m+ 3n=5 2m+ 1n=-1 Now that we have identified all of the variables and constants, we can place them in a matrix. [ cc|c 7 & 3 & 5 2 & 1 & -1 ]
In order to solve the matrix, we will use row operations to obtain a matrix in the following form. [ cc|c 1 & 0 & a 0 & 1 & b ] This final matrix represents the solution of the system of equations, where m= a and n= b. Let's solve the matrix!
(II): LHS * 3=RHS* 3
(I): Subtract (II)
(I): Subtract terms
(II): .LHS /3.=.RHS /3.
(I): LHS * 2=RHS* 2
(II): Subtract (I)
(II): Subtract terms
(I): .LHS /2.=.RHS /2.
We have found that m=8 and n=-17. Now we can find x and y. m&=1/x= 8/1 ⇒ x=1/8 n&=1/y=-17/1 ⇒ y=-1/17 The solution of the system is the point ( 18,- 117).