Pearson Algebra 2 Common Core, 2011
PA
Pearson Algebra 2 Common Core, 2011 View details
Cumulative Standards Review

Exercise 3 Page 189

Create an or compound inequality because the absolute value is greater than or equal to the given value.

A

Practice makes perfect
We are asked to find and graph the solution set for all possible values of n in the given inequality. |3x+12|≥ 3 To do this, we will create a compound inequality by removing the absolute value. In this case, the solution set is any number that makes the distance between 3x and - 12 greater than or equal to 3 in the positive direction or in the negative direction. 3x+12 ≥ 3 or 3x+12≤ - 3

Let's isolate x in both of these cases before graphing the solution set.

Case 1

3x+12≥ 3
3x≥- 9
x≥- 3
This inequality tells us that all values greater than or equal to - 3 will satisfy the inequality.

Case 2

3x+12≤- 3
3x≤- 15
x≤- 5
This inequality tells us that all values less than or equal to - 5 will satisfy the inequality.

Solution Set

The solution to this type of compound inequality is the combination of the solution sets. First Solution Set:& x≥- 3 Second Solution Set:& x≤ - 5 Combined Solution Set:& x≤ - 5 or x≥ - 3

Graph

The graph of this inequality includes all values less than or equal to - 5 or greater than or equal to - 3. We show this by keeping the endpoints closed.

This corresponds to option A.