Pearson Algebra 2 Common Core, 2011
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Pearson Algebra 2 Common Core, 2011 View details
1. Relations and Functions
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Exercise 48 Page 67

Try to rewrite this inequality as a compound inequality.

-3/2

Practice makes perfect
Before we can solve this equation, we need to isolate the absolute value expression.
|2x|+4<7
|2x|+4-4<7-4
|2x|<3
We are asked to find and graph the solution set for all possible values of x in the given inequality. |2x| < 3

To do this, we will create a compound inequality by removing the absolute value. In this case, the solution set is any number less than 3 away from the midpoint in the positive direction and any number less than 3 away from the midpoint in the negative direction. Absolute Value Inequality:& |2x| < 3 Compound Inequality:& - 3< 2x < 3 We can split this compound inequality into two cases, one where 2x is greater than - 3 and one where 2x is less than 3. 2x>- 3 and 2x < 3 Let's isolate x in both of these cases before graphing the solution set.

Case 1

2x<3
x<3/2
This inequality tells us that all values less than 32 will satisfy the inequality.

Case 2

2x>- 3
x>- 3/2
x>-3/2
This inequality tells us that all values greater than - 32 will satisfy the inequality.

Solution Set

The solution to this type of compound inequality is the overlap of the solution sets. Let's recombine our cases back into one compound inequality. First Solution Set:& x< 3/2 Second Solution Set:& -3/2 < x [0.8em] Intersecting Solution Set:& -3/2< x<3/2