Exercise 33 Page &nbsp; 66

C= 43

F=9/5( 43)+32

a/c* b = a* b/c

F=387/5+32

Calculate quotient

F=77.4+32

AddTerms

Add terms

F=109.4

Therefore, 43 degrees Celsius is equal to 109.4 Fahrenheit, which was the unknown value m.

b We want to find the missing measure for F in the following ordered pair.

(-12,n) Since the first value represents degrees in Celsius C, we will substitute -12 for C in our relation.

F=9/5C+32

C= -12

F=9/5( -12)+32

a/c* b = a* b/c

F= -108/5+32

Calculate quotient

F=-21.6+32

AddTerms

Add terms

F=10.4

Therefore, -12 degrees Celsius is equal to 10.4 Fahrenheit, which was the unknown value n.

c We want to find the missing measure of C in the following ordered pair.

(p,12) Since the second value represents degrees in Fahrenheit F, we will substitute 12 for F in our relation.

F=9/5C+32

F= 12

12=9/5C+32

SubEqn

LHS-32=RHS-32

-20=9/5C

a/c* b = a* b/c

-20=9C/5

MultEqn

LHS * 5=RHS* 5

-100 = 9C

DivEqn

.LHS /9.=.RHS /9.

-100/9= C

Calculate quotient

-11.111111 ... =C

RoundDec

Round to 1 decimal place(s)

-11.1 ≈ C

RearrangeEqn

Rearrange equation

C≈ -11.1

Therefore, 12 degrees Fahrenheit is equal to -11.1 Celsius, which was the unknown value p.

d We have to find the missing measure of C in the following ordered pair.

(q,19) Since the second value represents degrees in Fahrenheit F, we will substitute 19 for F in our relation.

F=9/5C+32

F= 19

19=9/5C+32

SubEqn

LHS-32=RHS-32

-13=9/5C

a/c* b = a* b/c

-13=9C/5

MultEqn

LHS * 5=RHS* 5

-65=9C

DivEqn

.LHS /9.=.RHS /9.

-65/9=C