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Pearson Algebra 2 Common Core, 2011

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Pearson Algebra 2 Common Core, 2011 View details

1. Relations and Functions

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Exercise 24 Page 65

To evaluate a function for a given value of the variable, substitute the value for the variable.

Value: - 52
Ordered Pair: ( 9,- 52)

Practice makes perfect

To evaluate a function for a certain value of x means that we substitute the given value for every instance of x. Let's do this for the given function when x=9.

f(x)=2/9x-9/2

x= 9

f( 9)=2/9( 9)-9/2

FracMultDenomToNumber

a/9* 9 = a

f(9)=2-9/2

a = 2* a/2

f(9)=4/2-9/2

Subtract fractions

f(9)=-5/2

When x=9, the function's value is - 52. The ordered pair that corresponds to this result is ( 9,- 52).

Subchapter links

Lesson Check p.64

Practice and Problem-Solving Exercises p.65-67

Standardized Test Prep p.67

Mixed Review p.67