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Pearson Algebra 2 Common Core, 2011

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Pearson Algebra 2 Common Core, 2011 View details

1. Relations and Functions

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Exercise 22 Page 65

To evaluate a function for a given value of the variable, substitute the value for the variable.

Value: 125
Ordered Pair: (- 1, 125)

Practice makes perfect

To evaluate a function for a certain value of x means that we substitute the given value for every instance of x. Let's do this for the given function when x=- 1.

f(x)=-12x/5

x= - 1

f( - 1)=-12( - 1)/5

a(- b)=- a * b

f(- 1)=-- 12/5

MoveNegFracToNum

Put minus sign in numerator

f(- 1)=- (- 12)/5

- (- a)=a

f(- 1)=12/5

When x=- 1, the function's value is 125. The ordered pair that corresponds to this result is (- 1, 125).

Subchapter links

Lesson Check p.64

Practice and Problem-Solving Exercises p.65-67

Standardized Test Prep p.67

Mixed Review p.67