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Pearson Algebra 2 Common Core, 2011

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Pearson Algebra 2 Common Core, 2011 View details

1. Relations and Functions

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Exercise 18 Page 65

To evaluate a function for a given value of the variable, substitute the value for the variable.

Value: 3
Ordered Pair: (- 5,3)

Practice makes perfect

To evaluate a function for a certain value of x means that we substitute the given value for every instance of x. Let's do this for the given function when x=- 5.

f(x)=-2x+1/3

x= - 5

f( - 5)=-2( - 5)+1/3

a(- b)=- a * b

f(- 5)=-- 2* 5+1/3

Multiply

f(- 5)=-- 10+1/3

Add terms

f(- 5)=-- 9/3

Calculate quotient

f(- 5)=- (- 3)

- (- a)=a

f(- 5)=3

When x=- 5, the function's value is 3. The ordered pair that corresponds to this result is (- 5,3).

Subchapter links

Lesson Check p.64

Practice and Problem-Solving Exercises p.65-67

Standardized Test Prep p.67

Mixed Review p.67