Pearson Algebra 2 Common Core, 2011
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Pearson Algebra 2 Common Core, 2011 View details
3. Right Triangles and Trigonometric Ratios
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Exercise 43 Page 925

Use the sine ratio to find b.

a≈ 19.8
b≈ 2.9
m ∠ A =81.7^(∘)

Practice makes perfect

First, let's draw the measurements from the exercise on a right triangle to visualize the given information.

We will find the missing measures one at a time. In this case, this means that we want to find a, b, and m ∠ A.

Side Lengths

We can find b using a sine ratio. The sine of ∠ B is the ratio of the length of the leg opposite ∠ B to the length of the hypotenuse. We know that b is equal to the length of the leg opposite ∠ B and that 20 is equal to the length of the hypotenuse. Therefore, we can write the following equation. sin B=Opposite/Hypotenuse ⇒ sin 8.3 ^(∘) =b/20 To solve this equation, we will first isolate b. Then, we will have to use the calculator to find the value of sin 8.3 ^(∘).
sin 8.3 ^(∘) =b/20
Solve for b
20(sin 8.3 ^(∘))=b
b=20(sin 8.3 ^(∘))
b≈20(0.14435)
b≈ 2.887124
b≈ 2.9
Now, we can find a using the Pythagorean Theorem. a^2 + b^2 = c^2 Let's substitute the known lengths, b = 2.9 and c= 20, into this equation to find a.
a^2+b^2=c^2
a^2 + 2.9^2= 20^2
Solve for a
a^2+8.41=400
a^2=391.59
a=sqrt(391.59)
a=19.78863...
a≈ 19.8

Angle Measures

To find m∠ A, recall that the acute angles of a right triangle are complementary. Therefore, m ∠ A and m ∠ B add up to 90^(∘). m ∠ A + m ∠ B = 90^(∘) Now, we can substitute the measure of ∠ B in our equation and find the measure of ∠ A. m ∠ A+8.3^(∘) = 90^(∘) ⇔ m ∠ A =81.7^(∘)