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In a right triangle, the cotangent of an acute angle is defined as the ratio of the length of the adjacent side to the angle to the length of the opposite side to the angle.
Triangle:
Trigonometric Ratios: sin θ=4sqrt(41)/41, cos θ=5sqrt(41)/41, tan θ=4/5, csc θ=sqrt(41)/4, sec θ=sqrt(41)/5
Given that cot θ= 54, we want to sketch a right triangle with θ as the measure of one acute angle. Then, we will find the other five trigonometric ratios of θ. Let's do these things one at a time.
In a right triangle the cotangent of an acute angle is defined as the ratio of the length of the adjacent side to the angle to the length of the opposite side to the angle.
cot θ =5/4 ⇔ cot θ = adjacent/opposite
We can find the length of the hypotenuse by substituting a= 5 and b= 4 into the Pythagorean Theorem.
a= 5, b= 4
Calculate power
Add terms
sqrt(LHS)=sqrt(RHS)
Rearrange equation
Note that when solving the equation we only considered the principal root. This is because c represents a side length and therefore must be a positive number. We can now draw the right triangle and label its three sides.
Having the three sides of the right triangle allows us to find the five remaining trigonometric ratios. Remember to rationalize denominators, if needed.
| Function | Substitute | Simplify |
|---|---|---|
| sin θ=opp/hyp | sin θ=4/sqrt(41) | sin θ=4sqrt(41)/41 |
| cos θ=adj/hyp | cos θ=5/sqrt(41) | cos θ=5sqrt(41)/41 |
| tan θ=opp/adj | tan θ=4/5 | - |
| csc θ=hyp/opp | csc θ=sqrt(41)/4 | - |
| sec θ=hyp/adj | sec θ=sqrt(41)/5 | - |
a/b=a * sqrt(41)/b * sqrt(41)
sqrt(a)* sqrt(a)= a
Let's now follow the same procedure to rationalize the denominator of5sqrt(41).
a/b=a * sqrt(41)/b * sqrt(41)
sqrt(a)* sqrt(a)= a