Sign In
In a right triangle, the cotangent of an acute angle is defined as the ratio of the length of the adjacent side to the angle to the length of the opposite side to the angle.
Triangle:
Trigonometric Ratios: sin θ=4sqrt(41)/41, cos θ=5sqrt(41)/41, tan θ=4/5, csc θ=sqrt(41)/4, sec θ=sqrt(41)/5
Given that cot θ= 54, we want to sketch a right triangle with θ as the measure of one acute angle. Then, we will find the other five trigonometric ratios of θ. Let's do these things one at a time.
Therefore, we know that the length of the adjacent side to θ is 5 and that the length of the opposite side to θ is 4.
a= 5, b= 4
Calculate power
Add terms
sqrt(LHS)=sqrt(RHS)
Rearrange equation
Having the three sides of the right triangle allows us to find the five remaining trigonometric ratios. Remember to rationalize denominators, if needed.
| Function | Substitute | Simplify |
|---|---|---|
| sin θ=opp/hyp | sin θ=4/sqrt(41) | sin θ=4sqrt(41)/41 |
| cos θ=adj/hyp | cos θ=5/sqrt(41) | cos θ=5sqrt(41)/41 |
| tan θ=opp/adj | tan θ=4/5 | - |
| csc θ=hyp/opp | csc θ=sqrt(41)/4 | - |
| sec θ=hyp/adj | sec θ=sqrt(41)/5 | - |
a/b=a * sqrt(41)/b * sqrt(41)
sqrt(a)* sqrt(a)= a
a/b=a * sqrt(41)/b * sqrt(41)
sqrt(a)* sqrt(a)= a