Pearson Algebra 2 Common Core, 2011
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Pearson Algebra 2 Common Core, 2011 View details
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Exercise 21 Page 963

Use the cosine ratio to find m∠ D.

d=8
m∠ D≈ 53.1^(∘)
m∠ E≈ 36.9^(∘)

Practice makes perfect

First, let's draw the measurements from the exercise on a right triangle to visualize the given information.

We will find the missing measures one at a time. In this case, this means that we want to find m∠ D, m∠ E, and d.

Angle Measures

We can find m∠ D using the cosine ratio.

The cosine of ∠ D is the ratio of the length of the leg adjacent ∠ D to the length of the hypotenuse. cos D=Adjacent/Hypotenuse ⇒ cos D=6/10 By the definition of the inverse cosine, the inverse cosine of 610 is the measure of ∠ D. To find it we can use a calculator.

m∠ D=cos ^(-1) 6/10
m∠ D =53.13010235... ^(∘)
m∠ D≈ 53.1^(∘)

To find m∠ E, recall that the acute angles of a right triangle are complementary. Therefore, m∠ D and m∠ E add to 90^(∘). m∠ D+m∠ E=90^(∘) Now, we can substitute the approximated measure of ∠ D in our equation and find the measure of ∠ E. 53.1^(∘) +m∠ E≈ 90^(∘) ⇔ m∠ E≈ 36.9^(∘)

Side Lengths

Finally we can find the measure of d. To do it we can use the Pythagorean Theorem. d^2+e^2=f^2 Let's substitute the known lengths, e= 6 and f= 10, into this equation to find d.

d^2+e^2=f^2
d^2+ 6^2= 10^2
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Solve for d
d^2+36=100
d^2=64
d=sqrt(64)
d=8