Pearson Algebra 2 Common Core, 2011
PA
Pearson Algebra 2 Common Core, 2011 View details
6. Angle Identities
Continue to next subchapter

Exercise 59 Page 950

The x-coordinate of the point at which the terminal side of the angle intersects the unit circle is defined as cos θ. Similarly, sin θ is the y-coordinate of that point.

sqrt(6)-sqrt(2)/4

Practice makes perfect

Consider the given angle. We can use it to draw a right triangle with one of its legs on the x-axis of a coordinate plane.

The length of the leg on the y-axis is the y-coordinate of P, which is sin α. The length of the other leg is the x-coordinate of P, which is cos α. Keep in mind that P is in Quadrant II. Therefore, the x-coordinate is negative which means that cos α is negative. P(x,y) = P(-cos α, sin α)

We can find the value of α knowing that a half of a circle is 180^(∘) and the given angle has a measure of 165^(∘) in the counterclockwise direction. α=180^(∘)-165^(∘) ⇔ α = 15^(∘) We will now focus on the right triangle.

Now, we need to find the exact value for sin 15^(∘) which is equivalent to sin 165^(∘). To do this, we will rewrite 15^(∘) as 45^(∘)-30^(∘). Before we rewrite the given expression, let's recall the values of the three main trigonometric functions for the most important angles.

sin θ cos θ tan θ
θ =0^(∘) 0 1 0
θ =30^(∘) 1/2 sqrt(3)/2 sqrt(3)/3
θ =45^(∘) sqrt(2)/2 sqrt(2)/2 1
θ =60^(∘) sqrt(3)/2 1/2 sqrt(3)
θ =90^(∘) 1 0 -
θ =180^(∘) 0 - 1 0
θ =360^(∘) 0 1 0
Let's now recall the Angle Difference Identity for a sine function sin(A-B)=sin A cos B-cos A sin B We will use this identity to rewrite the given expression.
sin(15^(∘))
cos( 45^(∘)- 30^(∘))
sin 45^(∘) cos 30^(∘) - cos 45^(∘) sin 30^(∘)
Next, we will use the table we constructed above to find the exact value of the expression. sin 45^(∘) cos 30^(∘) - cos 45^(∘) sin 30^(∘) = sqrt(2)/2 (sqrt(3)/2)- sqrt(2)/2 (1/2) Let's finally simplify the obtained expression!
sqrt(2)/2(sqrt(3)/2)-sqrt(2)/2(1/2)
Simplify
sqrt(2) * sqrt(3)/2 * 2-sqrt(2) * 1/2 * 2
sqrt(2 * 3)/2 * 2-sqrt(2) * 1/2 * 2
sqrt(2 * 3)/2 * 2-sqrt(2)/2 * 2
sqrt(6)/4-sqrt(2)/4
sqrt(6)-sqrt(2)/4
Therefore, the exact value for sin 165^(∘) is sqrt(6)-sqrt(2)4.