Pearson Algebra 2 Common Core, 2011
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Pearson Algebra 2 Common Core, 2011 View details
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Exercise 11 Page 825

Start by finding the formula, then use it to find the next two terms.

Next Two Terms: 4 and 1
Formula: a_1 = 16, a_n=a_(n-1) - 3
Explicit or Recursive? Recursive

Practice makes perfect
We want to find a formula for the given sequence. 16, 13 10, 7, ...

Notice that every term in the sequence is 3 less than the previous term. We will use this to find the formula.

a_1 a_2 a_3 a_4 ... a_n
16 13 10 7 ... —
a_1 a_1 - 3 a_2 - 3 a_3 - 3 ... a_(n-1) -3

Since the formula describes the n^(th) term using the (n-1)^\text{th} term, it is a recursive formula. Let's use it to find the next two terms.

a_n=a_(n-1) - 3
a_5=a_(5-1) - 3 a_6=a_(6 - 1) - 3
a_5=a_4 - 3 a_6=a_5 - 3
a_5=7 - 3 a_6=4 - 3
a_5=4 a_6=1

Alternative Solution

Finding an explicit formula

Alternatively, we can find an explicit formula for the sequence. To do so, notice that each term is 3 less than the previous term, with the first term 3 less than 19.

a_1 a_2 a_3 a_4 ... a_n
16 13 10 7 ... —
19 - 1*3 19 - 2*3 19 - 3*3 19 - 4* 3 ... 19 - n* 3

Since the formula describes the n^(th) term using the number n, it is an explicit formula. Let's use it to find the next two terms.

a_n=19 - n* 3
a_5=19 - 5* 3 a_6=19 - 6* 3
a_5=4 a_7=1