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Pearson Algebra 2 Common Core, 2011 View details

10. Normal Distributions

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Exercise 39 Page 745

Recall that _nC_x= n!x!(n-x)!.

≈ 0.1612

Practice makes perfect

If we have n repeated independent trials, each with a probability of success p and a probability of failure q, then the Binomial Probability of x successes in the n trials can be found by the following formula. P(x)= _nC_x p^x q^(n-x) We are told that p= 0.4. With the value of p and knowing that p+q=1, we can calculate the value of q.

p+q=1

Substitute

p= 0.4

0.4+q=1

SubEqn

LHS-0.4=RHS-0.4

q= 0.6

We are also told that x= 2 and n= 9. We can substitute all of these values into the formula and evaluate the right-hand side.

P(x)= _nC_x p^x q^(n-x)

SubstituteValues

Substitute values

P( 2)= _9C_2 ( 0.4)^2 ( 0.6)^(9- 2)