body{margin:0;} noscript{z-index: 10000; position: fixed; display: block; height: 100%; width: 100%; background: #fff;} noscript .fa{font-size: 40px; display:block; color: #daa520;} noscript div{margin-top: 6%; padding-left: 20px; padding-right: 20px; text-align: center;} ! You must have JavaScript enabled to use this site.

Pearson Algebra 2 Common Core, 2011

PA

Pearson Algebra 2 Common Core, 2011 View details

10. Normal Distributions

Continue to next subchapter

Exercise 27 Page 744

To start, find the difference between the mean of the data set and the upper bound of the given interval.

84 %

Practice makes perfect

We know that the set of data is normally distributed with a mean of 100 and a standard deviation of 10. We will find the probability of choosing a value that is at most 110. x≤ 110 First, let's find the difference between 110 and the mean 100.

110- 100= 10 Then, we will divide the difference by the standard deviation 10. 10/10=1 Thus, 110 is 1 standard deviation above the mean. To find the probability, we will shade the percent of data which is no more than 1 standard deviation above the mean.

Finally, we can find the percent of the data by adding the percents of the shaded areas.

p=0.15 %+2.35 %+13.5 %+34 %+34 %

Add terms

p=84 %

The probability of choosing a random value that is at most 110 is equal to 84 %.

Subchapter links

Lesson Check p.743

Practice and Problem-Solving Exercises p.743-745

Standardized Test Prep p.745

Mixed Review p.745