Pearson Algebra 2 Common Core, 2011
PA
Pearson Algebra 2 Common Core, 2011 View details
10. Normal Distributions
Continue to next subchapter

Exercise 25 Page 744

To start solving, find the difference between the mean of the data set, and the lower and upper bounds of the given interval.

81.5 %

Practice makes perfect
We know that the set of data is normally distributed with a mean of 100 and a standard deviation of 10. We will find the probability of choosing a value that is between 90 and 120. 90 ≤ x≤ 120 First, let's find the difference between 90 and the mean 100. 90- 100= - 10

Now, let's find the difference between 120 and the mean 100. 120- 100= 20 Then, we will divide the differences by the standard deviation 10. - 10/10=- 1and20/10=2 Thus, 90 is 1 standard deviation below the mean and 120 is 2 standard deviations above the mean. To find the probability, we will shade the percent of data which is at most 1 standard deviation below the mean and no more than 2 standard deviations above the mean.

Finally, we can find the percent of data by adding the percents of the shaded areas.
p=34 %+34 %+13.5 %
p=81.5 %
The probability of choosing a random value between 90 and 120 is equal to 81.5 %.