Pearson Algebra 2 Common Core, 2011
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Pearson Algebra 2 Common Core, 2011 View details
10. Normal Distributions
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Exercise 23 Page 744

To start solving, find the difference between the mean of the data set, and the lower and upper bounds of the given interval.

47.5 %

Practice makes perfect
We know that the set of data is normally distributed with a mean of 100 and a standard deviation of 10. We will find the probability of choosing a value that is between 80 and 100. 80 ≤ x≤ 100 First, let's find the difference between 80 and the mean 100. 80- 100= - 20

Now, let's find the difference between 100 and the mean 100. 100- 100= 0 Then, we will divide the differences by the standard deviation 10. - 20/10=- 2and0/10= Thus, 80 is 2 standard deviations below the mean and 100 is standard deviations from the mean. To find the probability, we will shade the percent of data which is at most 2 standard deviations below the mean and at most equal to the mean.

Finally, we can find the percent of the data by adding the percents of the shaded areas.
p=13.5 %+34 %
p=47.5 %
The probability of choosing a random value between 80 and 100 is equal to 47.5 %.