Pearson Algebra 2 Common Core, 2011
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Pearson Algebra 2 Common Core, 2011 View details
10. Normal Distributions
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Exercise 15 Page 743

To start solving, find the difference between the mean of the data set and the given interval.

68 %

Practice makes perfect
We know that the set of data is normally distributed with a mean of 50 and a standard deviation of 8. We will find the percent of the data that is between 42 and 58. 42 ≤ x≤ 58 First, let's find the difference between 42 and the mean 50. 42- 50= - 8

Now, let's find the difference between 58 and the mean 50. 58- 50= 8 Then, we will divide the differences by the standard deviation 8. - 8/8=- 1and8/8=1 Thus, 42 is 1 standard deviation below the mean and 58 is 1 standard deviation above the mean. To find the percent, we will shade the percent of data which is at most 1 standard deviation below the mean and at most 1 standard deviation above the mean.

Finally, we can find the percent of the data by adding the percents of the shaded areas.
p=34 %+34 %
p=68 %
The percentage of the data between 42 and 58 is equal to 68 %.