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Recall the formula for the expansion of (a+b)^n stated by the Binomial Theorem.
20c^3d^3
To find the 4^(th) term of the binomial expansion, we should recall the Binomial Theorem. It states that for every positive integer n, we can expand the expression (a+b)^n by using the numbers in the n^(th) row of Pascal's Triangle.
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(a+b)^n = P_0 a^nb^0 + P_1 a^(n-1)b + ... + P_(n-1) ab^(n-1) + P_n a^0b^n |
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(a+b)^n = _nC_0 a^nb^0 + _nC_1 a^(n-1)b + ... + _nC_(n-1) ab^(n-1) + _nC_n a^0b^n |
Next, let's recall the formula to calculate the combination _nC_x. _nC_x ⇔ n!/x!(n-x)! We will use this to substitute the values of the combinations in the formula for the binomial expansion.
| (a+b)^n = _nC_0 a^nb^0 + _nC_1 a^(n-1)b + ... + _nC_(n-1) ab^(n-1) + _nC_n a^0b^n |
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| ( c+ d)^6= 1 c^6 d^0+ 6 c^5 d^1+ 15 c^4 d^2+ 20 c^3 d^3+ 15 c^2 d^4+ 6 c^1 d^5+ 1 c^0 d^6 |
a^0=1
a^1=a
a * 1=a
_6C_0= 6!/0!(6-0)!
Subtract terms
Cancel out common factors
Simplify quotient
0!=1
a/a=1