Pearson Algebra 2 Common Core, 2011
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Pearson Algebra 2 Common Core, 2011 View details
6. Analyzing Data
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Exercise 26 Page 717

Practice makes perfect
a Consider the given frequency table.
Score 1 2 3 4 5
Frequency 1 3 f 12 3

We are asked to find the value of f in the table. Since we are told that the mean of the scores is 3.5, we can use it to find f. Let's begin by recalling the definition of mean.

Mean=Sum of the data values/Number of values

Since we are given a frequency table, we have to multiply each score by its frequency in order to find the sum of the data values. Let's find this sum and simplify! 1(1)+3(2)+f*3+ 12(4) + 3(5) ⇓ Sum of the data values= 3f+70 The total number of values is the sum of the frequencies of each score. 1+3+f+12+3 ⇓ Number of values = f+19 We will now use the definition of mean to write and solve an equation for f.

Mean=Sum of the data values/Number of values
3.5=3f+70/f+19
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Solve for f
3.5(f+19)=3f+70
3.5f + 66.5 = 3f+70
3.5f+66.5 - 3f=70
0.5f+66.5 = 70
0.5f=70-66.5
0.5f = 3.5
0.5f * 2 = 3.5(2)
f=7

We found that f=7. This means that 7 students scored 3 in the exam.

b We found in Part A that f=7. Let's use this to rewrite the given frequency table!
Score 1 2 3 4 5
Frequency 1 3 7 12 3

The mode is the value or values that appear most often in a data set. Since we are given a frequency table, the mode is the value with the highest frequency.

Score 1 2 3 4 5
Frequency 1 3 7 12 3

Therefore, the mode of the scores is 4.

c When the data is arranged in numerical order the median is the middle value — or the mean of the two middle values — of the set. Let's use our frequency table from Part B and list all the scores.
1, 2, 2, 2, 3, 3, 3, 3, 3, 3, 3, 4, 4, 4, 4, 4, 4, 4, 4, 4, 4, 4, 4, 5, 5, 5 Since we have 26 values, which is an even number, the median is the mean of the two middle values. Median=4+ 4/2=4