Exercise 16 Page 716

If a value in a data set is more than 1.5 times the interquartile range away from the lower or upper quartiles, it is considered an outlier. Therefore, to identify any outliers, we first have to find these statistical measures including any outliers.

Analyzing the Data With Any Outliers

Let's organize the information in a list using a graphing calculator. Press STAT, and choose Edit. Enter all of the data into the first list.

Next, analyze the data by pressing the STAT button again and navigating to the CALC menu. Press ENTER once to select the 1-Var Stats option and then again to select the list in which we entered the data (usually L1). This will produce most of the statistical measures we are looking to find.

Let's write the obtained mean, median, lower quartile, and upper quartile. rcl x:& 684.9 &(mean) Q_1:& 589 &(lower quartile) med:& 661 &(median) Q_3:& 884.5 &(upper quartile) To find the mode, we have to identify the value that occurs most frequently. &103, 515, 582, 596, 619,626,661, & 728, 757,869,900,947,1001 We see that there is no value that occurs more frequently than others, so there is no mode in the given data set.

Identifying Outliers

To identify any outliers, we start by calculating the interquartile range (IQR). This is the difference between the upper and lower quartiles. Q_3- Q_1= IQR ⇕ 884.5- 589= 295.5 Next, we need to determine the maximum and minimum values for data to be considered outlier. Outliers are more than 1.5 times the IQR away from the upper and lower quartiles. Q_1-1.5*IQR:& 589-1.5( 295.5) = 145.75 Q_3+1.5*IQR:& 884.5+1.5( 295.5) = 1327.75 These calculations tell us that any values lower than 145.75 or greater than 1327.75 are outliers. Since 103 is less than 145.75, we know that 103 is an outlier.

Analyzing the Data Without the Outliers

Let's repeat the process, excluding 103 from the data set. Type the new data set into another list, L2.

Once we finish adding the new data set into L2, we can analyze the data the same way as before. After selecting the 1-Var Stats option, however, remember to choose L2 by pushing 2nd and 2.

Examining the new output will give us most of the desired statistical measures. rcl x:& 733.4 &(Mean) med:& 694.5 &(Median) Note that there is still no value that occurs more frequently than others. Therefore, there is still no mode of the data set.

Summary

Finally, we summarize our findings in the table below so it is easier to compare the results.

We can see that removing the outlier modified the mean and the median. Without the outlier, the mean and the median increased.