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Try to rewrite this inequality as a compound inequality.
Solution Set: -11/15 ≤ t ≤ 17/15
Graph:
Before we can solve this inequality, we need to isolate the absolute value expression using the Properties of Inequality.
We are asked to find and graph the solution set for all possible values of t in the given inequality. |5t-1| ≤ 14/3
LHS+1≤RHS+1
a = 3* a/3
Add fractions
.LHS /5.≤.RHS /5.
.a/b /c.= a/b* c
This inequality tells us that all values less than or equal to 1715 will satisfy the inequality.
LHS+1≤RHS+1
a = 3* a/3
Add fractions
.LHS /5.=.RHS /5.
.a/b /c.= a/b* c
Rearrange inequality
This inequality tells us that all values greater than or equal to - 1115 will satisfy the inequality.
The solution to this type of compound inequality is the overlap of the solution sets. Let's recombine our cases back into one compound inequality. First Solution Set:& t ≤ 17/15 Second Solution Set:& -11/15 ≤ t Intersecting Solution Set:& -11/15 ≤ t ≤ 17/15
The graph of this inequality includes all values from - 1115 to 1715, inclusive. We show this by using closed circles on the endpoints.