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Try to rewrite this inequality as a compound inequality.
Solution Set: -11/15 ≤ t ≤ 17/15
Graph:
To do this, we will create a compound inequality by removing the absolute value. In this case, the solution set is any number less than or equal to 143 away from the midpoint in the positive direction and any number less than or equal to 143 away from the midpoint in the negative direction. Absolute Value Inequality:& |5t-1| ≤ 14/3 Compound Inequality:& - 14/3≤ 5t-1 ≤ 14/3 We can split this compound inequality into two cases, one where 5t-1 is greater than or equal to - 143 and one where 5t-1 is less than or equal to 143. - 14/3≤5t-1 and 5t-1≤ 14/3 Let's isolate t in both of these cases before graphing the solution set.
LHS+1≤RHS+1
a = 3* a/3
Add fractions
.LHS /5.≤.RHS /5.
.a/b /c.= a/b* c
LHS+1≤RHS+1
a = 3* a/3
Add fractions
.LHS /5.=.RHS /5.
.a/b /c.= a/b* c
Rearrange inequality
The solution to this type of compound inequality is the overlap of the solution sets. Let's recombine our cases back into one compound inequality. First Solution Set:& t ≤ 17/15 Second Solution Set:& -11/15 ≤ t Intersecting Solution Set:& -11/15 ≤ t ≤ 17/15
The graph of this inequality includes all values from - 1115 to 1715, inclusive. We show this by using closed circles on the endpoints.