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Start by identifying the values of each term's coefficient.
(w+10)(3w+2)
We want to completely factor the given expression. Here we have a quadratic trinomial of the form aw^2+bw+c, where |a| ≠1 and there are no common factors. To factor this expression, we will rewrite the middle term, bw, as two terms. The coefficients of these two terms will be factors of ac whose sum must be b.
3w^2+32w+20 ⇔ 3w^2+32w+20
We have that a= 3, b=32, and c=20. There are now three steps we need to follow in order to rewrite the above expression.
c|c|c|c 1^(st)Factor &2^(nd)Factor &Sum &Result 1 &60 &1 + 60 &61 2 & 30 & 2 + 30 &32
Finally, we will factor the last expression obtained.
Factor out w
Factor out 10
Factor out (3w+2)
Therefore, we have found that the factored form of the given expression is (w+10)(3w+2).
Distribute (w+10)
Distribute 3w
Distribute 2
Add terms
We can see above that after expanding and simplifying, the result is the same as the given expression. Therefore, we can be sure our solution is correct!